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An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward

with the horizontal.
What is the magnitude of the velocity when it hits the ground?

User Theowi
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1 Answer

27 votes
27 votes

Answer:

Step-by-step explanation:

Angle:

β = - 23°

( From the symmetry condition)

An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward-example-1
User Magnus
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