Question

Question help

a. a hemispherical bowl of radius a contains water to a depth h. find the volume of the water in the bowl.

Answer 1

The volume of the hemisphere is:
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" \frac{2}{3} [/tex]
`\pi` * h³ " ;

or; write as: "
`(2 \pi h^3)/(3)` " .
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Step-by-step explanation:
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The formula/equation for the volume, "V", of a sphere:

V = (
`(4)/(3)`) *
`\pi` * r³ ;

The depth; or, height, "h"; would represent the "radius", "r" .

So, the volume would be:

V =
`(1)/(2)` *
`(4)/(3)` *
`\pi` * h³ ;
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Note: "
`(1)/(2)` *
`(4)/(3)` " ;

=
`((1*4))/((2*3)) = (4)/(6) = ((4/2))/((6/2)) = (2)/(3)` ;
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The volume of the hemisphere is:

" \frac{2}{3} [/tex]
`\pi` * h³ . "

or; write as: "
`(2 \pi h^3)/(3)` " .
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