80.9k views
0 votes
Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a screen 4.0 meters away. The first order bright band lines are 2.0 E -2 meters away from the central bright maxima. What is the distance between the slits?

1.3 E -4 m
8.0 E -6 m
3.2 E -9 m
7.8 E3 m

2 Answers

3 votes

Answer:

1.3 E -4 m

Step-by-step explanation:

I took the test :)

User LorenzoValentijn
by
8.4k points
3 votes

Answer:

The distance between the slits is given by 1.3 ×
10^(-4) m

Given:


\lambda = 6.4 * 10^(-7) m

D = 4 m

y =
2 * 10^(-2) m

m = 1

To find:

distance between slits, d = ?

Formula used:

y =
(m * \lambda * D)/(d)

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits


\lambda = wavelength

Solution:

distance of first bright band from central maxima is given by,

y =
(m * \lambda * D)/(d)

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits


\lambda = wavelength

Thus,

d =
(m * \lambda * D)/(y)

d =
(1 * 6.4 * 10^(-7) * 4 )/(2 * 10^(-2) )

d = 1.28 ×
10^(-4)

d = 1.3 ×
10^(-4) m

The distance between the slits is given by 1.3 ×
10^(-4) m

User Taseenb
by
8.1k points