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Demonstrate at least two different ways how to solve the equation 5^(2x+1)=25 Help! I need one way to be the Logarithmic method
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Demonstrate at least two different ways how to solve the equation 5^(2x+1)=25

Help! I need one way to be the Logarithmic method

User Roy Van Santen
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5^(2x+1)=25 = ln5^(2x+1)=ln25 = (2x+1)ln5=ln25 = 2x+1=ln25-ln5 = 2x=ln5-1 = x=1/2*ln5-1 is exact form or approx.=-0.195

hope this helps! if you want another way to solve besides using logs then just let me know. Thanks!
User Alexsandro Souza
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