Question

What is the mass of 3.6 x 1024 atoms of Zinc (Zn)?

Answer 1

The mass of 3.6 x 10^24 atoms of Zinc (Zn) is 392.19 grams.

Step-by-step explanation:

The molar mass of Zinc (Zn) is 65.4 g/mol. This means that for every mole of Zinc, you have 65.4 grams. To find the mass of 3.6 x 1024 atoms of Zinc, we need to convert the number of atoms to moles and then multiply by the molar mass.

First, calculate the number of moles:

3.6 x 1024 atoms / 6.022 x 1023 atoms/mol = 5.98 moles

Then, multiply the moles by the molar mass:

5.98 moles x 65.4 g/mol = 392.19 grams

Therefore, the mass of 3.6 x 1024 atoms of Zinc is 392.19 grams.

Answer 2

Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) = 3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.