Question

Use the distance formula to find the distance, to the nearest tenth, from S(6, −2) to V(−4, 3). −5.0 units 3.1 units 11.2 units 8.7 units

Answer 1

11.2 units is the answer

Answer 2

`~~~~~~~~~~~~\textit{distance between 2 points} \\\\ S(\stackrel{x_1}{6}~,~\stackrel{y_1}{-2})\qquad V(\stackrel{x_2}{-4}~,~\stackrel{y_2}{3})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ SV=√([-4 - 6]^2 + [3 - (-2)]^2)\implies SV=√((-10)^2+(3+2)^2) \\\\\\ SV=√(125)\implies SV\approx 11.18\implies \underset{\textit{rounded up}}{SV\approx 11.2}`