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33 votes
At a temperature of 302 K, the gas in a cylinder has a volume of 10.0 liters. If the volume of the gas is decreased to 20.0 liters, what must the temperature be for the gas pressure to remain constant?

A. 140k
B. 273k
C. 604k
D. 5,600k

User NorseGaud
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2.1k points

2 Answers

12 votes
12 votes

Answer:

604 K

Step-by-step explanation:

" If the volume of the gas is INCREASED to 20.0 liters ......"

P1V1/T1 = P2V2/T2 Since P1 and P2 are equal:

V1/T1 = V2/T2

V1 = 10 L V2 = 20 L

10 / 302 = 20 / T2 shows T2 = 604 K

User Charles Harris
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2.9k points
11 votes
11 votes

Answer: The temperature after decreasing the volume is 604 k

Step-by-step explanation:

Given data:

Initial temperature T1 = 302 k

Initial volume v1 = 10 liters

Volume of the gas is reduced to 20 liters ( v2)

According to Charles law " if pressure is constant the temperature and volume will be directly proportional".

That is :

v1 / T1 = v2 / T2

The unknown temperature is T2

Hence by substituting the known values in above equation

10 / 302 = 20/ T2

T2 = 604 k

Hence the temperature T2 after volume change to 20 liters by keeping pressure constant is 604 k

User Aluko
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3.7k points