Answer: The temperature after decreasing the volume is 604 k
Step-by-step explanation:
Given data:
Initial temperature T1 = 302 k
Initial volume v1 = 10 liters
Volume of the gas is reduced to 20 liters ( v2)
According to Charles law " if pressure is constant the temperature and volume will be directly proportional".
That is :
v1 / T1 = v2 / T2
The unknown temperature is T2
Hence by substituting the known values in above equation
10 / 302 = 20/ T2
T2 = 604 k
Hence the temperature T2 after volume change to 20 liters by keeping pressure constant is 604 k