Answer:
9 cm to 1 s. f.
Explanation:
If we draw 2 radii from a point on the circle to both ends of the chord, we get an isosceles triangle with height 4 cm and equal sides of 6 cm. This consists of 2 right triangles of height 4 , hypotenuse 6 cm and base equal to half the length of the chord.
By Pythagoras:
6^2 = 4^2 + b^2 where b = base.
b = √(6^2 - 4^2)
= √20
= 4.472 cm
So, the length of the chord = 2 * 4.472
= 8.944 cm.