Answer: 27 & 13/21
Your teacher may want you to delete the & symbol.
====================================================
Step-by-step explanation:
Let's convert each mixed number to an improper fraction.
We'll start with 6 & 2/3
The formula to use is this
a & b/c = (a*c + b)/c
So,
a & b/c = (a*c + b)/c
6 & 2/3 = (6*3 + 2)/3
6 & 2/3 = (18 + 2)/3
6 & 2/3 = 20/3
The mixed number 6 & 2/3 converts to the improper fraction 20/3
Now do the same for the other mixed number as well.
a & b/c = (a*c + b)/c
4 & 1/7 = (4*7 + 1)/7
4 & 1/7 = (28 + 1)/7
4 & 1/7 = 29/7
----------------------------------
The task is to now multiply these improper fractions
Recall that (a/b)*(c/d) = (a*c)/(b*d)
We multiply across the numerators separately and multiply across the denominators separately.
So,
(20/3)*(29/7) = (20*29)/(3*7) = 580/21
The last step is to convert this to a mixed number.
Use a calculator to get 580/21 = 27.6190476190476 approximately.
The stuff to the left of the decimal is the whole part 27, aka the quotient.
The decimal part is then multiplied with the denominator (21) to get 0.6190476190476*21 = 13 which is the remainder.
Quotient = 27, remainder = 13, so 580/21 = 27 remainder 13 = 27 & 13/21