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How many real solutions does 5x^2+7x+1=0 have? explain your answer.

User Foredoomed
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1 Answer

3 votes

Answer:

2

Explanation:

The graph of 5x^2+7x+1 crosses the x-axis (x=0) twice, so there are 2 real solutions.

_____

The discriminant is b^2 - 4ac, where a=5, b=7, c=1. Its value is ...

... 7^2 -4·5·1 = 29

This value is greater than 0, indicating there are two (2) real roots. They are ...

... (-7±√29)/10

How many real solutions does 5x^2+7x+1=0 have? explain your answer.-example-1
User Freeforall Tousez
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