Question

How many carbon atoms are present in 1.84 moles of C2H6O?

Answer 1

2.22x10^24 carbon atoms. Each C2H6O molecule has 2 carbon atoms, so there is 1.84 * 2 = 3.68 moles of carbon atoms. To convert from moles to individual atoms, just multiply by Avogadro's number, so 3.68 * 6.0221409x10^23 = 2.21615x10^24 Rounding to 3 significant digits gives 2.22x10^24 carbon atoms.

Answer 2

Answer is: there are 2,208·10²⁴ cabron atoms.
n(C₂H₆O) = 1,84 mol.
In one mol of C₂H₆O, there is two mol of carbon.
n(C) = 2 · n(C₂H₆O).
n(C) = 2 · 1,84 mol.
n(C) = 3,68 mol.
N(C) = n(C) · Na.
N(C) = 3,68 mol · 6·10²³ 1/mol.
N(C) = 2,208·10²⁴.
Na - Avogadro number.