If a gas sample has a pressure of 30.7 kpa at 0.00, by how many degrees celsius does the temperature have to increase to cause the pressure to double?

Question

asked Jul 4, 2019 104k views

1 Answer

Ivan Ivanovich · Answer 1 · 2019-07-11T20:39:39+0000

Answer: The temperature has to increase by
.

Step-by-step explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$ (At constant volume and number of moles)

(P_1)/(T_1)=(P_2)/(T_2)

where,

P_1 = initial pressure of gas = 30.7 kPa

P_2 = final pressure of gas =
2* 30.7=61.4kPa

T_1 = initial temperature of gas =
0^0C=(0+273)K=273K

T_2 = final temperature of gas = ?

(30.7)/(273)=(61.4)/(T_2)

T_2=546K=(546-273)^0C=273^0C

Therefore, the temperature has to increase by
to increase to cause the pressure to double.