200k views
5 votes
Whats the circumcenter of ΔEFG with e(2,6) ,f(2,4) and g(6,4)

User Lrsppp
by
5.8k points

1 Answer

4 votes
you need to find the distance between the 3 lengths of the lines from the given points
ef = sqrt ( 6-4) ^2 + 2-2^2) = sqrt 4 = 2
fg = sqrt (6 - 2)^2 + 4-4^2 = sqrt16 = 4
ge = sqrt (6-4)^2 + (2-6)^2) = sqrt 20 = 4.47
circumference = 2 + 4 + 4.47 = 10.47
User Tim Robinson
by
6.7k points