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Evaluate ∫ cot 2x dx. A. ½ Ln cos 2x + C B. ½ Ln sec 2x + C C. ½ Ln sin 2x + C D. ½ Ln csc 2x + C
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Evaluate ∫ cot 2x dx. A. ½ Ln cos 2x + C B. ½ Ln sec 2x + C C. ½ Ln sin 2x + C D. ½ Ln csc 2x + C
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Feb 5, 2019
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Evaluate ∫ cot 2x dx.
A. ½ Ln cos 2x + C
B. ½ Ln sec 2x + C
C. ½ Ln sin 2x + C
D. ½ Ln csc 2x + C
Mathematics
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Salabaha
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∫ cot 2x dx=
∫ ((cos (2x))/(sen(2x)) dx
u=
sen(2x)
du=2cos(2x)dx
∫ ((1/2)*(1/u))du=
(1/2)*Ln(u) + C
(1/2)*Ln(sen(2x)) + C
answer
C. ½ Ln sin 2x + C
Yogzzz
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Feb 11, 2019
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Yogzzz
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