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a rectangular field has an area of 1452 square feet. if the width is three times greater than the length, what is the length of the field

2 Answers

3 votes
width=3x
length=x
Area of a rectangle=length x width
We have to solve the following equation.
x(3x)=1452
3x²=1452
x²=1452/3
x²=484
x=+√484=22

length=x=22 feet
width=3x=3(22 feet)=66 feet.

Answer: the length of the field would be 66 feet.
User GLee
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7.9k points
6 votes

Answer:

The length of the rectangular field is 22 feets.

Explanation:

Let us write
w for the width and
l for the length.

From the data we know that
w=3l.

By the formula of the area of a rectangle
A=w*l. Then, substituting
w=3l into the formula for the area:
A=3l^2.

So, we have the equation
1452=3l^2, which is equivalent to
484=l^2. Then, taking square roots in both sides:
l=\pm 22, but as we are looking for a measure we discard the negative solution. Therefore,
l=22 feets.

User Nasar Kushnir
by
7.8k points