Question

Describe, in detail, how to make 2.0 liters of a 1.0 molar HCl solution from a 12.5 molar HCl stock solution.

Answer 1

Answer: We require 0.16 L of HCl stock solution to make a 2 L of 1 molar HCl solution.

Step-by-step explanation:

To form a solution of 1M HCl solution from a stock solution of hydrochloric acid, we use the formula:

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the molarity and volume of the stock solution.

`M_2\text{ and }V_2` are the molarity and volume of the given HCl solution.

We are given:

`M_1=12.5M\\V_1=?L\\M_2=1M\\V_2=2L`

Putting values in above equation, we get:

`12.5* V_1=1* 2\\\\V_1=0.16L`

Hence, we require 0.16 L of HCl stock solution to make a 2 L of 1 molar HCl solution.

Answer 2

We are starting with a 12.5 M HCl solution. We want 2.0 L of a 1.0 M HCl solution.

We can start with the solution we want to make and work backwards to determine how much of the 12.5 M solution is required.

2.0L x 1.0 mol/L = 2.0 moles HCl

To make 2 L of a 1.0M solution of HCl, we need 2.0 moles of HCl that we get from the stock solution.

2.0 moles HCl / 12.5 mol/L = 0.16 L = 160 mL of solution.

Therefore, we need 160 mL of the 12.5 M solution of HCl to make 2 L of a 1.0M HCl solution.