Question

The standard reaction free energy =δg0−311.kj for this reaction: p4 (s) + 20hf (g) → 4pf5 (g) + 10h2 (g) use this information to complete the table below. round each of your answers to the nearest kj .

Answer 1

1. -198 J/ k

2. -5 J/K

3. -148 J/K

Step-by-step explanation:

Answer 2

Answers are:
Standard reaction: P₄ + 20HF→ 4PF₅ + 10H₂.
1) chemical reaction: 1/5P₄ + 4HF→ 4/5PF₅ + 2H₂.
ΔG = -311kJ ÷ 5 = -62,2 kJ.
2) chemical reaction: 12PF₅ + 30H₂ → 3P₄ + 60HF.
ΔG = -311kJ · (-3) = 933 kJ.
3) chemical reaction: 4PF₅ + 10H₂ → P₄ + 20HF.
ΔG = -311kJ · (-1) = 311 kJ, reversed standard reaction.