Answer:
= 8(2x + 3)³
Explanation:
Differentiate using the chain rule
Given
y = f(g(x)) , then
= f'(g(x)) × g'(x)
Here
f(x) = ⇒ f'(x) = 4(2x + 3)³
g(x) = 2x + 3 ⇒ g'(x) = 2
Thus
= 4(2x + 3)³ × 2
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= 8(2x + 3)³ = f'(g(x)) × g'(x)
⇒ f'(x) = 4(2x + 3)³ = 4(2x + 3)³ × 2