Question

PLEASE HELP WITH THIS MATH PROBLEM 30 POINTS

Here is a pic of the problem.

A carpenter builds a rectangular bookcase that is 120 cm long and 62 cm tall. The carpenter uses two braces along the diagonals to support the bookcase.

What is the length of the one of the braces, to the nearest tenth of a centimeter?

Enter your answer as a decimal.

Answer 1

Use formula A²+B²=C²
120²+62²=C²
14,400+3,844=C²
14,400+3,844=18,244
√18,244=135.07035...

135.07035...≈135.1

Answer 2

The measure of one of the braces is 135.1 cm.

Explanation:

It is given that A carpenter builds a rectangular bookcase that is 120 cm long and 62 cm tall. The carpenter uses two braces along the diagonals to support the bookcase.

From the figure drawn, let two braces be AC and BD. then, the value of one of the braces is:

Since, the measure of ∠C=90°, Using Pythagoras theorem in ΔBDC, we have

`(BD)^2=(BC)^2+(DC)^2`

Substituting the given values, we have

`(BD)^2=(62)^2+(120)^2`

`(BD)^2=3844+14400`

`(BD)^2=18244`

`BD=135.1 cm`

Therefore, the measure of one of the braces is 135.1 cm.