Question

A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees. Find the area of the triangle.

Answer 1

b. 61.3 cm 2

Explanation:

I got it correct on my edge just now.

Answer 2

The area of the triangle is 61.2 sq. cm.

Explanation:

Given : A triangle has sides of lengths 10 cm and 16 cm and the measure of the angle between them is 130 degrees.

To find : The area of the triangle?

Solution :

The area of triangle when two sides and one angle between them is given is

`A=(1)/(2)* a* b* \sin\theta`

Where, a and b are the sides of the triangle

a=10 cm and b=16 cm

`\theta=130^\circ` is the angle between two sides

Substituting the values in the formula,

`A=(1)/(2)* 10* 16* \sin 130`

`A=80* 0.766`

`A=61.28cm^2`

Therefore, The area of the triangle is 61.2 sq. cm.