Question

What is the standard form of (1+2√-3)/(1+√-3)

Answer 1

1.75+0.43301270i
hope this helped and let me know if i was right plz

Answer 2

`(7)/(4) +(3)/(4) i`

Explanation:

`(1+2√(-3) )/(1+√(-3))`

To remove the negative sign from square root use 'i'

square root (-1) is 'i'

`(1+2√(3)i)/(1+√(3)i)`

Multiply top and bottom by conjugate of
`(1+√(3)i)`

Conjugate of
`(1+√(3)i)` is
`(1-√(3)i)`

Multiply it at the top and bottom

`(1+2√(3)i)/(1+√(3)i) \cdot (1-√(3)i)/(1-√(3)i)`

Multiply numerator and denominator using FOIL method

`(1-√(3)i+2√(3)i-3i^2)/(1+3)`

the value of i^2 is -1

`(1+√(3)i-6(-1))/(4)`

`(1+√(3)i+6)/(4)`

`(7+√(3)i)/(4)`

`(7)/(4) +(3)/(4) i`