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Hello, I have a question about quadratic equations. I don’t know how to slove these:

1. (x-6)(2x-6)=20
2. (x+3) ² = 8x+12
3. (3x-1)(x+5)=3x ²

can somebody help me?

User Nabdreas
by
8.7k points

2 Answers

4 votes

Answer:


Explanation:


User Olleh
by
8.9k points
3 votes

Answer:

1.X= 8 or 1

2.X= 3 or -1

3. X = 5/14

Explanation:

1. Expanding your original equation (x-6)(2x-6)=20) , you get 2x^2-18x+36=20. Then, subtract 20 from both sides. You get 2x^2-18x+16=0. Now this is a standard Quadratic equation. Use the quadratic Formula to solve this, you get X= 8 or 1.

2. 1. Expand : x²+6x+9-8x-12=0 2. Simplify : x^2-2x-3=0 3. Solve as a quadratic equation : x= 3 or -1.

3. Same thing as the first one!

Hope I helped! <3


User Cmosig
by
7.4k points