Answer:
Explanation:
3n^2+4n+20
Let's do group factoring.
First, multiply the leading coefficient by the constant and find a combination that satisfies 4n.
3*20=60 3*20, 10*6
10*6 satisfies 4n since 10-6=4
So
3n^2+10n-6n+20 Group
(3n^2+10n)(-6n+20) Take out the greatest common factor in each section.
n(3n+10)-2(3+10) Combine like terms
(n-2)(3n+10)
To find n make each equation equal zero
n-2=0 Add 2 to both sides
n=2
3n+10=0 Subtract 10 from both sides
3n=-10 Divide both sides by 3
n= -10/3