Question

A capacitor stores 7.6 x 10^-11 C when the electric potential difference between the plates is 5.8 v. What is the electric potential energy in the capacitor

Answer 1

Use the formula for energy stored between the plates of a capacitor:

`E = (1)/(2)QU=(1)/(2)7.6\cdot 10^(-11)C\cdot 5.8V= 2.2\cdot 10^(-10)J`

where Q is he charge (given) and U is the electric potential (aka voltage), given.

The stored energy is 2.2 10^{-10} Joules.