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A family has two cars. The first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas. During

one particular week, the two cars went a combined total of 1325 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of
the two cars that week?

User Qwww
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Answer:

  • The
    20 mile-per-gallon car consumed
    40 gallons, whereas
  • The
    15 mile-per-gallon car consumed
    35 gallons.

Explanation:

Assume that the
20 mile-per-gallon car consumed all that
75 gallons of fuel. How far would the cars have travelled?


20 * 75 = 1500\; \text{miles}.

This assumption overestimated the total mileage of the two cars by
1500 - 1325 = 175\; \text{miles}. Here's why: for every gallon that the second (
15 mile-per-gallon) car consumed, this assumption would overestimate the total mileage by
20 - 15 = 5\; \text{miles}. Therefore, the overestimation of
175\; \text{miles} corresponds to:


\begin{aligned} & 175\; \text{miles overestimated} \\ & * \left(\frac{1\; \text{gallon consumed by the second car}}{5\; \text{miles overestimated}}\right)\\ &= (175)/(5)\; \text{gallons consumed by the second car} \\ &= 35\; \text{gallons consumed by the second car}\end{aligned}.

Therefore, the second car consumed
35\; \text{gallons}. The first car would have consumed
75 - 35 = 40\; \text{gallons}.

Verify the results:
40 * 20 + 35* 15 = 1325\; \text{miles}.

User Abhay Prince
by
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