Answer:
The correct option is C. The given graph represents the function f(x)=sin(x).
Explanation:
From the given graph it is clear that the initial value of the function is 0.
The maximum value of function is 1 at
.
The minimum value of function is -1 at
.
The period of the function is 2π.
The x-intercepts are 0, π, 2π.
These are the properties of a positive sine function. The given graph represents the function f(x)=sin(x).
Therefore the correct option is C.
To confirm the solution find the value of each function at x=0, and
. The function must be satisfy by the points (0,0) and

For option (1),


Therefore option 1 is incorrect.
For option (2),


Therefore option 2 is incorrect.
For option (3),



Therefore option 3 is correct.
For option (4),



Therefore option 4 is incorrect.