Question

Find the solution of the system equations
8x- 10y = 38 -4x - 2y = -26

Answer 1

`-4x-2y=-26\\-2y=--26+4x\\(-2y)/(-2) =(-26)/(-2) +(4x)/(-2) \\y=13-2x...(3)`

Plug the third equation in the first equation

`8x-10(13-2x)=38\\8x-130+20x=38\\8x+20x=38+130\\28x=168\\(28x)/(28) =(168)/(28) \\x= 6`

y=13-2x

∴y=13-2(6)

y=13-12

y=1

Hope this helps