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Solve the following system. y = x 2 - 9x + 10 and x + y + 5 = 0. Enter the solution with the smaller x value first.

The solutions are ( __a0, __ a1) and ( __a2, __ a3)

User Alasarr
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1 Answer

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Answer:

Solutions are (3, -8) and (5, -10)

Explanation:

From the equation x + y + 5 = 0 :-

x = -y - 5

Substitute for x in the other equation:

y = (-y - 5)^2 - 9(-y-5) + 10

y = (y^2 + 10y + 25) + 9y + 45 + 10

y^2 + 18y + 80 = 0

( y + 8)(y + 10) = 0

y = -8, -10

Substitute these values of y in the equation x + y + 5 = 0:-

x = -8:-

x - 8 + 5 = 0 so x = 8-5 giving.x = 3

x = -10:-

x - 10 + 5 = 0 sox = 10-5 giving x = 5


User Aurelius
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