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For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12

User Dale Zak
by
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1 Answer

3 votes

Answer: p = 6


Explanation:

HI !


px + 3y - ( p-3)=0


a₁ = p , b₁ = 3 , c₁ = - (p-3)


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12x + py - p=0


a₂ = 12 , b₂ = p , c₂ = -p


since , the equations have infinite solutions ,


a₁/a₂ = b₁/b₂ = c₁/c₂


p/12 = 3/p = p-3/p



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p/12 = 3/p


cross multiply ,


p² = 36


p = √36

p = 6


for the value of p = 6 , the equations will have infinitely many solutions





User Vprajan
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