Question

The force needed to lift a 3000 N truck using a jack with a MA of 15

Answer 1

As we know that mechanical advantage is defined as

`MA = (F_o)/(F_(in))`

now here we have

`MA = 15`

also we have

`F_O = 3000 N`

now we will have

`15 = (3000)/(F_(in))`

now we will have

`F_(in) = (3000)/(15)`

`F_(in) = 200 N`

so our applied force will be 200 N