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What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

1 Answer

5 votes

Answer:

remainder = 290

Explanation:


(3x^3-4x^2+2x+8)/(x-5)

= 3x² + 11x + 57 +
(290)/(x-5)

quotient = 3x² + 11x + 57 and remainder = 290


User DhrubaJyoti
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