Question

The intensity of a sound decreases by a factor of 4. As a result, the sound intensity level decreases by___.

A.4dB
B.6dB
C.8dB
d.16dB

Answer 1

Option B is the correct answer.

Step-by-step explanation:

We have expression for sound intensity level,

`L=10log_(10)(I)/(I_0)`, where I is the intensity.

Here new intensity is given by 4I.

So, increase in sound intensity level

`\delta L=10log_(10)(4I)/(I_0)-10log_(10)(I)/(I_0)=10log_(10)(4I)/(I)=6dB`

So, option B is the correct answer.