Answer: The approximate solution is (-0.36, 2.08).
Explanation:
Given system of equations :
x+5y=10 and 3x+y=1.
Let us solve the system of equation by substitution.
Solving second equation 3x+y=1 for y first.
3x+y=1.
Subtracting 3x from both sides, we get
3x-3x+y=1-3x
y = 1-3x.
Substituting y=1-3x in first equation x+5y=10, we get
x+ 5(1-3x) = 10.
x + 5 -15x =10
-14x +5 = 10.
Subtracting 5 from both sides, we get
-14x +5-5 = 10-5
-14x =5
Dividing by -14 on both sides, we get
-14x/-14=5/-14
x= -0.36.
Plugging x=-0.36 in second equation y=1-3x, we get
y = 1-3(-0.36) = 1+1.08 = 2.08.
Therefore, approximate solution is (-0.36, 2.08).