Question

In how many ways can the letters of the word INDEPENDENCE be arranged if all the words start with N and end with P.

Answer 1

1663200

Explanation:

in the word independance there are 3n,4e,&2d,1l, and 1c

since letters are repeating we use the formula,

n!/p1!p2!p3!

total letters=12

so n=12

since 3n, 4e & 2d

p1=3, p2=4

p3=2

total arrangments= 12!/3!4!2!

=1663200