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How many molecules of isopently acetate C7H1402 are released (1x10^ -6g) in a typical bee sting

User Yun Huang
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The number of molecules of isopently acetate is 4.63 x 10¹⁵ molecules

calculation

Step 1: find the moles of isopently acetate( C₇H₁₄O₂)

moles = mass÷ molar mass

From periodic table the molar mass of C₇H₁₄O₂

= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol

moles = 1 x10⁻⁶ g÷ 130 g/mol = 7 x 10⁻⁹ moles

step 2 ; use the Avogadro's law constant to calculate the number of molecules

That is according to Avogadro's law 1 mole = 6.02 x 10²³ molecules

7 x 10⁻⁹ moles = ? molecules

by cross multiplication

= { (7 x 10⁻⁹ moles x 6.02 x10²³ molecules) / 1 mole} = 4.63 x 10¹⁵ molecules

User Jesse Roper
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