Answer:
The magnitude of the car's resultant vector is 15.72.
Explanation:
A car travels 10km southeast,
And then 15 km in a direction 60 degrees north of east.
We have to find,
The magnitude of the car's resultant vector.
According to the question,
To resultant direction calculate by using the sum of vectors following all the steps given below.
A car travels 10 km southeast,
And then 15 km in a direction 60 degrees north of east.
The first vector has module is 10 and angle is 315°,
In the south direction, the angle is 270° and east is 360°,
So the angle in southeast,
The second vector has module 15 and angle = 40°
Decompose both vectors in their horizontal and vertical component
The horizontal component of the first vector is,
The vertical component of the first vector is,
The horizontal component of the second vector is,
The vertical component of the second vector is,
The sum of the horizontal component of the resultant vector is,
And the sum of the vertical component of the resultant vector is,
The magnitude of the vector (14.57km, 5.91km) is:
Therefore,
The magnitude of the car's resultant vector is,
Hence, The required magnitude of the car's resultant vector is 15.72.