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17 votes
A 2.0 x 10^3 kilogram car collides with a tree and is brought to

rest in 0.50 seconds by an average force of 6.0 x 10^4 newtons.
What is the magnitude of the impulse on the car during this
0.50 second interval?

User Simon Gill
by
5.0k points

1 Answer

7 votes

Answer:

P = 30000 [kg*m/s]

Step-by-step explanation:

Momentum in physics is defined as the product of force in the given time interval. In this way, it can be expressed by means of the following equation.


P=F*t

where:

P = momentum [kg*m/s]

F = force = 6*10⁴ [N]

t = 0.5 [s]

Now replacing:


P=6*10^(4)*0.5\\P=30000[kg*m/s]

User AshHimself
by
4.7k points