Question

Find the distance between the two points shown in the coordinate plane below to the nearest hundredth.

(-2, -2)
(3, 4)

Answer 1

7.81

Explanation:

Given points (-2,-2) and (3, 4)

To find distance between points we apply distance formula

`D = √((x_2-x_1)^2+(y_2-y_1)^2)`

(x1,y1) is (-2,-2) and (x2,y2) is (3,4)

Plug in the values in the formula

`D = √((3-(-2))^2+(4-(-2))^2)`

`D = √((5)^2+(6)^2)`

`D = √(25+36)`

`D = √(61)`

D= 7.810249676

Round to nearest hundredth

So distance = 7.81