A lightbulb has a resistance of 195 ohms and carries a current of 0.62 A. The power rating of the lightbulb, to the nearest whole number is blank W.

asked Mar 25, 2019 21.0k views

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2 votes

Answer:

75 w

Step-by-step explanation:

Antek answered Mar 26, 2019

by Antek

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3 votes

Wattage = I^2 * R

R = 195 ohms

I = 0.62 A

Wattage = 0.62^2 * 195

Wattage = 74.958

Wattage = 75 watts to the nearest whole watt.

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