Question

A lightbulb has a resistance of 195 ohms and carries a current of 0.62 A. The power rating of the lightbulb, to the nearest whole number is blank W.

Answer 1

75 w

Step-by-step explanation:

Answer 2

Wattage = I^2 * R

R = 195 ohms

I = 0.62 A

Wattage = 0.62^2 * 195

Wattage = 74.958

Wattage = 75 watts to the nearest whole watt.