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integration \: of (1)/(2) ln(2x {^(2) )

User Towr
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1 Answer

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Using properties of the logarithm, you can rearrange the integrand as


\frac12\ln(2x^2)=\frac{\ln2+\ln x^2}2=\frac{\ln2+2\ln x}2=\ln\sqrt2+\ln x

Then recall that the integral of
\ln x is


\displaystyle\int\ln x\,\mathrm dx=x(\ln x-1)+C

(or you can find that out by integrating by parts) and so


\displaystyle\int\frac12\ln(2x^2)\,\mathrm dx=(\ln\sqrt2)x+x(\ln x-1)+C

User Neolei
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