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Evaluate using the finite geometric sum formula

Evaluate using the finite geometric sum formula-example-1
User Dan Albert
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5.5k points

2 Answers

6 votes

Answer:

The correct choice is b. -18.703


User Kingchris
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5.6k points
5 votes

Answer:


S_9=-18.703.

Explanation:

The given series is,


\sum_(i=1)^9(-(1)/(2))^(i-1)

When we substitute
i=1, we get the first term, which is
a_1=-28(-(1)/(2))^(1-1)


This implies that,


a_1=-28(-(1)/(2))^(0)



a_1=-28(1)=-28.


The common ratio is


r=-(1)/(2)


The finite geometric sum is given by the formula,


S_n=(a_1(r^n-1))/(r-1) , -1\:<\:r<\:1.


Since there are 9 terms, we find the sum of the first nine terms by putting
n=9 in to the formula to get,



S_9=(-28((-(1)/(2))^9-1))/(-(1)/(2)-1).



S_9=(-28((-(1)/(2))^9-1))/(-(1)/(2)-1).



S_9=(-28((-(1)/(512))-1))/(-(3)/(2)).



S_9=(-28(-(513)/(512)))/(-(3)/(2)).



S_9=-28((171)/(256)).



S_9=-(1197)/(64).




S_9=-18.703.


The correct answer is B





User ZeroGraviti
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5.7k points