Question

Two cruise ships left port at the same time. The distance Ship A traveled is modeled by the function d(t)=47t where d represents distance in miles and t represents time in hours. Ship B traveled a total of 165 miles in 3 hours. How does the distance Ship A traveled in 1 hour compare to the distance Ship B traveled in 1 hour?

The distance Ship A traveled in 1 h is equal to the distance Ship B traveled in 1 h.

The distance Ship A traveled in 1 h is greater than the distance Ship B traveled in 1 h.

The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.

Answer 1

The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.

Answer 2

Option 3 - The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.

Explanation:

Given : Two cruise ships left port at the same time. The distance Ship A traveled is modeled by the function d(t)=47t where d represents distance in miles and t represents time in hours. Ship B traveled a total of 165 miles in 3 hours.

To find : How does the distance Ship A traveled in 1 hour compare to the distance Ship B traveled in 1 hour?

Solution :

Ship B traveled a total of 165 miles in 3 hours.

In 3 hour ship traveled 165 miles

In 1 hour ship traveled
`(165)/(3)=55` miles.

Distance traveled by Ship B in 1 hour is 55 miles.

The distance Ship A traveled is modeled by the function
`d(t)=47t` where d represents distance in miles and t represents time in hours.

Distance traveled in 1 hour is put t=1,

`d(t)=47(1)=47`

Distance traveled by Ship A in 1 hour is 47 miles.

So, The distance Ship A traveled in 1 h is less than the distance Ship B traveled in 1 h.

Therefore, Option 3 is correct.