Question

Which lines have slope -4/5 and contains point (0,1)?

Answer 1

ANSWER

The required line is BC


Step-by-step explanation

We want to find the line that passes through

`(0,1)`

and has slope

`m = - (4)/(5)`


Since the x-value of the given point is zero, the point


`(0,1)`

is the y-intercept.


From the above graph, the two lines that contains

`(0,1)`

are line CE and line BC.

Since, the slope


`m = - (4)/(5)`
is negative, line BC is the required line because it is sloping backwards.


We can confirm this by using the point,



`B(-5,5)`

and


`C(0,1)`


to find the slope and obtain



`m = (5 - 1)/( - 5 - 0) = - (4)/(5)`