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an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor line is 105ft long. how far from the tower can it be placed to 1dp?

User Rperryng
by
6.8k points

1 Answer

3 votes

Answer:

Let x be how far from the tower can it be placed

by Pythagorus theorem

x^2 + 96^2 = 105^2

x=√(105^2 -96^2 )=√1809 = 42.532340 = 42.5 ft


an anchor line for a tower needs to be replaced. the tower is 96ft tall. the anchor-example-1
User Benathon
by
6.2k points
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