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Simplify 4(3x^2y^4)^3/(2x^3y^5)^4 show your work

User Mokuril
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1 Answer

5 votes

Answer:

27/ (4 x^6 y^8)

Explanation:

4(3x^2y^4)^3/(2x^3y^5)^4

expand

4 (3^3 x^2^4 y^4^3) / (2^4 x^3^4 y^5^4)

power of the power rule , exponents to the power are multiplied

4 (3^3 x^(2*4) y^(4*3) / (2^4 x^(3*4) y^(5*4))

4 (27 x^(8) y^(12) / (16 x^(12) y^(20))

put like terms over each other

4 * (27/16) * x^8/x*16 * y^12/y^20

when dividing exponents , we subtract the powers

27 * 4/16 * x^ (8-14) * y^ (12-20)

27* 1/4 * x^(-6) * y^ (-8)

27/4 * x^(-6)(y)^ (-8)

negative terms go to the denominator

27/ (4 x^6 y^8)


User Justin Iurman
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