Answer:
2 x y^2 (x y - 1) (x y - 3)
Explanation:
2x^3y^4-8x^2y^3+6xy^2
each term contains 2xy^2 so factor that out
2xy^2(x^2y^2 -4xy+3)
then lets factor the inside
what terms multiply together to give us +3 and add to -4
-3* -1 = 3 -3+-1 =-4
2 x y^2 (x y - 1) (x y - 3)