Question

Factor completely 2x^3y^4-8x^2y^3+6xy^2

Answer 1

2 x y^2 (x y - 1) (x y - 3)

Explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2(x^2y^2 -4xy+3)

then lets factor the inside

what terms multiply together to give us +3 and add to -4

-3* -1 = 3 -3+-1 =-4

2 x y^2 (x y - 1) (x y - 3)