Question

An apple dropped from an apple tree. The height of the tree was 2.5 m. What was the final speed of the apple right before landing?

The correct answer is 7 m/s. I have no clue how!! Pls help!!

Answer 1

The correct answer to the question is : 7 m/s.

Step-by-step explanation:

As per the question, the apple is at a height h = 2.5 m.

The initial velocity of the apple u = 0

We are asked to calculate the final velocity [ v ] of the apple before touching the ground.

As the apple is falling under gravity, then the acceleration produced on the apple is nothing else than acceleration due to gravity.

Hence, acceleration a = g =
`9.8\ m/s^2`

From equation of kinematics , we know that -

`v^2-u^2\ =\ 2as`

⇒
`v^2=\ u^2+2gh`

⇒
`v^2=\ 0^2+2* 9.8* 2.5`

⇒
`v^2=\ 49`

⇒
`v=\ √(49)\ m/s`

⇒
`v=\ 7\ m/s` [ans]

Hence, the final velocity is 7 m/s.