Answer:
The mass of A and B together is 125kg
Step-by-step explanation:
To solve this problem, we set up the equations expressing the net force acting on A and B (forces acting to the right are +, those acting to the left are -):
![m_B\cdot a_B=F - F_(fr)\\m_A\cdot a_A = F_(fr)\\a_A = a_B](https://img.qammunity.org/2019/formulas/physics/middle-school/ltg7pnbmy1up46ffvk3tgoyxfznrp0nsss.png)
The net force acting on B is due to the acting pull force 100N less friction force caused by A. The net force on A is due to the friction force caused by the block B. Since we know both blocks accelerate at the same rate, the system can be solved easily:
![(m_B+m_A)\cdot a_B=F\\(m_B+m_A)\cdot 0.800 (m)/(s^2)=100N\implies\\m_B+m_A = (100N)/(0.800(m)/(s^2))kg= 125kg](https://img.qammunity.org/2019/formulas/physics/middle-school/wmnmwrbfgd86d3oq4lnttoow8kn09yxz76.png)
Of course, alternatively, in this very simple case you could consider A+B a single object being pulled with 100N, and obtain the same results by diving the pull force by the acceleration.