Answer: C
Explanation:
∑ 8()⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8()⁽¹⁻¹⁾
= 8 =
n = 2 → 8()⁽²⁻¹⁾
= =
n = 3 → 8()⁽³⁻¹⁾
n = 4 → 8()⁽⁴⁻¹⁾
n = 5 → 8()⁽⁵⁻¹⁾
Sum =
= 408.99
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)⁽ⁿ⁻¹⁾ from n = 1 to n = 5)⁽¹⁻¹⁾
)⁽²⁻¹⁾
= 
)⁽³⁻¹⁾
= 
)⁽⁴⁻¹⁾
= 
)⁽⁵⁻¹⁾
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