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What is the equation of the line that passes through the point (6,-7) and has a slope of -3/2

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The point-slope form:


y-y_1=m(x-x_1)

We have the point (6, -7) and the slope m = -3/2. Substitute:


y-(-7)=-(3)/(2)(x-6)\\\\\boxed{y+7=-(3)/(2)(x-6)}


y+7=-(3)/(2)(x-6) use distributive property


y+7=-(3)/(2)x+9 subtract 7 from both sides


\boxed{y=-(3)/(2)x+2}


y=-(3)/(2)x+2 multiply both sides by 2


2y=-3x+4 add 3x to both sides


\boxed{3x+2y=4}

Answer:

point-slope form:
y+7=-(3)/(2)(x-6)

slope-intercept form:
y=-(3)/(2)x+2

standard form:
3x+2y=4

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